rwmb_my_custom_field_after_save_field can't update my own fields in the database

This topic has 2 replies, 2 voices, and was last updated 5 years, 8 months ago by [email protected].

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April 25, 2019 at 12:19 AM #14264
[email protected]
Participant
Hello,

I'm using metabox type user with the custom table users.

I want to use this action:
```
add_action( 'rwmb_my_custom_field_A_after_save_field', 'usuario_aprobado_con_codigo_acceso' , 20, 5 );
function usuario_aprobado_con_codigo_acceso ( $null, $field, $new, $old, $post_id ) {
```
Depending of the field my_custom_field_A (the value is in $new), I want to update another custom field of the custom table users, my_custom_field_B

I see in another posts
https://support.metabox.io/topic/using-custom-attributes-from-rwmb_before_save_post-action/
something like this:
```
$storage = $field['storage'];
$storage->update( $post_id, 'last_name', "blablabla" );
```
And it run well, it update the filed last_name. It run well with the populate user fields.

But if I want to update another custom fields that I added in this table, I don't know what I have to do to update the value...
I try:

$storage->update( $post_id, 'my_custom_field_B', "blablabla" );

don't work...
I try a query:
```
    global $wpdb;
    $wpdb->update('usuarios', array( 'my_custom_field_B' => 'blablabla'), array( 'ID' => $post_id ) ); 
```
and don't work...

Do you know what I'm doing wrong?

Thanks,
Sergio

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April 25, 2019 at 10:05 AM #14267
Anh Tran
Keymaster
Hi Sergio,

Did you try:
```
add_action( 'rwmb_field_A_after_save_field', function ( $null, $field, $new, $old, $object_id ) {
    $storage = $field['storage'];
    $storage->update( $object_id, 'field_B', 'new value' );
}, 10, 5 );
```
This code works only when the field A is put after field B in the meta box, which means field B is already saved.

If field A is before field B, then after we run this code, field B still use value from the submission. In this case, please try this code:
```
add_action( 'rwmb_field_A_after_save_field', function ( $null, $field, $new, $old, $object_id ) {
    $_POST['field_B'] = 'new value'; // Modify directly submitted value from $_POST.
}, 10, 5 );
```
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April 25, 2019 at 8:10 PM #14283

[email protected]
Participant

Yes, I try the first method but don't run.

But with the second:
$_POST['field_B'] = 'new value';
It run well!!!

Thanks once again.

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